Example 1: Water from H2 and O2
Balanced: 2H2 + O2 → 2H2O. Given 4.00 g H2 and 32.0 g O2, find the limiting reactant and yield of H2O.
- n(H2) = 4.00 g / 2.016 g·mol−1 = 1.984 mol.
- n(O2) = 32.0 g / 32.00 g·mol−1 = 1.000 mol.
- Stoichiometric ratios: need 2 mol H2 per 1 mol O2. Ratios: H2: 1.984/2 = 0.992; O2: 1.000/1 = 1.000 → limiting is H2.
- Product moles: n(H2O) = 2 × 0.992 = 1.984 mol → mass = 1.984 × 18.015 = 35.7 g.