Example 1: Glucose (C6H12O6)
- Identify atomic masses: C = 12.011, H = 1.008, O = 15.999 g/mol.
- Multiply by subscripts: 6×C + 12×H + 6×O.
- Compute: (6×12.011) + (12×1.008) + (6×15.999) = 72.066 + 12.096 + 95.994 = 180.156 g/mol.
Enter a chemical formula to calculate its molar mass.
Molar Mass
180.156 g/mol