Enthalpy of Hydration: $CuSO_4$ to $CuSO_4 \cdot 5H_2O$
To determine the enthalpy change ($\Delta H_{hyd}$) for the hydration of anhydrous Copper (II) Sulfate to form Copper (II) Sulfate Pentahydrate using Hess’s Law.
$\text{CuSO}_{4(s)} + 5\text{H}_2\text{O}_{(l)} \rightarrow \text{CuSO}_4 \cdot 5\text{H}_2\text{O}_{(s)}$
Direct measurement of hydration energy is impossible without creating a solution. We use an indirect route:
Calculate heat ($q$) using $q = m \cdot c \cdot \Delta T$.
Convert to molar enthalpy: $\Delta H = -q/n$ (where $n = 0.025$).
Finally, subtract $\Delta H_2$ from $\Delta H_1$ to find the hydration energy.
You will dissolve each salt separately and use Hess's Law (ΔHhyd = ΔH₁ − ΔH₂). Predict the heat effects first, then lock it to unlock Start Test.
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Please click on one of the salt jars on the bench to prepare your sample.